switch statements calling a function

tekmorph · 10-19-2004, 12:20 PM

Hello I am new to c++ so please take it easy on me. What I am trying to do is nothing awesome, only call a function that multiplies 2 numbers and outputs a third. This function is called ....aaah I'm sure you know.... here is the code..I get the error
switch.cpp:4: error: too few arguments to function `int doit(int, int, int)'
switch.cpp:29: error: at this point in file
I thought I had enough arguments, I actually thought functions do not even need arguments, that they would just be declared void?
=========================================================
#include <iostream>
using namespace std;
int doit(int x, int y,int z) ////declaring my function doit
{ cout << "Give me a number\n"; ////asking for an int
cin >> x;
cout << "Give me another number\n"; //// asking for the second
cin >> y;
z= x*y; ////setting z to the return value
return (z); //// will this return z for the
//// function?
}
int main()
{
int a; //// the case switch constant
cout << "What would you like to do?\n";
cout << "1:Multiply two numbers\n";
cout << "2:Nothing?\n";
cin >> a; ////case value
switch (a)
{
case 1:
int doit(int x, int y, int z); ////call to doit()
break;

case 2:
cout << "Cya\n";
break;
}
int b= doit(); ////I think this is where I messed
cout <<"\n"<<b<<"\n"; ///it up

return 0;
=======================================================
thanks in advance.......flame away

Cedrik · 10-19-2004, 02:03 PM

Why passing argument to doit() function as it does not need it ?

Code:

#include <iostream>
using namespace std;
int doit()
{
    int x,y,z;
    cout << "Give me a number\n"; 
    cin >> x;
    cout << "Give me another number\n";
    cin >> y;
    z= x*y; 
    return (z); 
}

int main()
{
    int a, b;
    cout << "What would you like to do?\n";
    cout << "1:Multiply two numbers\n";
    cout << "2:Nothing?\n";
    cin >> a;
    switch (a) {
        case 1:
            b = doit();
            cout <<"\n"<<b<<"\n";
            break;

        case 2:
            cout << "Cya\n";
            break;
    }
    return 0; 
}

tekmorph · 10-19-2004, 05:53 PM

Very cool thank you for taking the time to look at that for me, as for your question I am not sure as to why I passed an argument to the function. I see it works perfect without. I am new and learning, but thank you very much for your help.