I have a small program that I am trying to write. The point of the program is to accept 3 parameters: -h | -b buf | source | target

The -h if active, creates a file with holes
The -b nbuf is supposed to allow the user to enter a specified amount for the buffer when reading and writing to a file.

The source is the source file and the target is a target file. The code that I have so far is as follows. One problem that I am having is that I receive the following errors upon compilation:

my.c: In function `main':
my.c:15: warning: assignment makes integer from pointer without a cast
my.c:19: warning: passing arg 1 of `read' makes integer from pointer without a cast
my.c:19: warning: passing arg 2 of `read' makes pointer from integer without a cast
my.c:32: warning: passing arg 1 of `write' makes integer from pointer without a cast
my.c:32: warning: passing arg 2 of `write' makes pointer from integer without a cast
my.c:33: warning: passing arg 1 of `lseek' makes integer from pointer without a cast

Below is the code that I have written

You'll actually need to open the file first, etc. You can't read directly from a filename. You need to open() the file using the filename. open() will return a file descriptor and you use that file descriptor for doing all the file operations like read()'ing and write()'ing. When you're doing playing with the file you'll need to close() it.

LOL, thanks I forgot that is required.

If I can open the file with:

int count;
int openfile;

if((openfile = open(argv[3],O_CREAT)) < 0)
error....
else
while (count != EOF)
{
lseek(argv[3],count++,SEEK_SET);
}

argv[3] meaning the source file. I'm a little unclear on pointers actually so how could I use the pointers in the read or write command.

You'd pass openfile to lseek() instead of argv[3].

Thanks, I appreciate your help.

The second parameter that the user sends to the program is the buffer that is used to write.

int buffer;
buffer = argv[2];

If I use this in a write function, for example:

write(opentarget,buffer,1);

I receive the error: arg 2 of `write' makes pointer from integer without a cast

I know that if buffer was a char and I was making it equal to a char, I would just have to add & after the = sign. What would be required for this?

bump

you declared buffer to be a integer and then your trying to assign it a char string from argv

this is your error


also isnet write a low level file operation or am i trippen on somethin ?

I dont remeber much of low level file operations but why is there a 1 in the write function at the end ?

HUH????? no that would make it assign right

char buffer

buffer = argv[3] <--- argv[3] is a string

maybe look at the getopt function
in stdlib.h for parsing command line arguments?

man section 3c on solaris.