Hi ,

I am trying to calculate delay between the two network interfaces

I tried using do_gettimeofday()function

But i am seeing that the resolution what i am getting is around minimumof 10ms

I am trying to calculate this on a MIPS platform

I tried testing it in following way

i am adding portion of code

struct timeval tv1,tv2
do_gettimeofday(&tv1);
udelay(100);
do_gettimeofday(&tv2);

When i tried tv2.tv_sec -tv1.tv_sec as well as tv2.tv_usec -tv1.tv_usec

the value returned is Zero.

The behaviour is the same when applied mdelay(3) instead of udelay in the above snippet.

What is the minimum resolution that i can get ?

if it is less than 10ms how can i get low resolution values

Regards
krishna

gettimeofday() will not easily give you such resolution, try clock_gettime() instead.