public static String[] ParsePowers(String[] InString)
{
String[] OutString = InString;

char[] TestMe;
int[] counter = new int[10];
counter[0] = 0;
while (counter[0] < (InString.Length - 1))
{
TestMe = OutString[(counter[0] + 1)].ToCharArray();
Console.WriteLine("{0}", TestMe[0]);
if (TestMe[0] == '^')
{
OutString = ReString(OutString, counter[0], (counter[0] + 2), DoPower(OutString[counter[0]], OutString[(counter[0] + 2)]));
}
counter[0]++;
}

return OutString;
}

public static string DoPower(String One, String Two)
{
double DOne = System.Convert.ToDouble(One);
double DTwo = System.Convert.ToDouble(Two);
double Out = DOne;
int counter = 0;

while (counter < DTwo)
{
Out = Out * DOne;
counter++;
}

String OutS = Out.ToString();
return OutS;
}

with this tester:

public class Tester
{
static void Main()
{
// public static String[] ParseOne(String InString)
String UHG = "2.2^2.2";

String[] Blug;

Blug = StringMath.ParseOne(UHG);

Blug = StringMath.ParsePowers(Blug);

int counter = 0;
while (counter < Blug.Length)
{
Console.WriteLine("{0}", Blug[counter]);
counter++;
}
}
}

note: ParseOne output the string 2.2^2.2 to a strign array with 2.2 in index 0, ^ in index 1, and 2.2 in index 2.

error:

Uncaught exception: System.FormatException: The supplied value did not have the correct format
at System.Private.NumberParser.ParseDouble(String, NumberStyles, NumberFormatInfo) in ./System/Private/NumberParser.cs:1219
at System.Double.Parse(String, NumberStyles, IFormatProvider) in ./System/Double.cs:127
at System.Double.Parse(String) in ./System/Double.cs:149
at System.Convert.ToDouble(String) in ./System/Convert.cs:2420
at StringMathNS.StringMath.DoPower(String, String)
at StringMathNS.StringMath.ParsePowers(String[])
at Tester.Main()
I tried a writeline and found the bug occurs in the parse to double section (duh, but ti double confirmed it)

what woudl the problem likely be? the ParseOne function works fine.

I dont know what the prblem is but each type (like double) has a method names parse() which converts the given string to its type.
Hope it helps!

Thank you for the help, I ended up writing my own functions/methods to change a string into a double :-D here it is for those who want to share the code:
First you need to convert the String into a char array, after that it is easy to just pump it in (you can convert the string to a char array with: char[] CA = StringVar.ToCharArray() )


public static double MakeDouble(char[] InChar)
{
double Temp = 0, Temp2 = 0;
int[] counter = new int[10];
char TestChar;
bool NotAfterD = true;
double[] Casting = new double[2];
counter[0] = 0;
counter[1] = 0;
counter[2] = 1;

while (counter[0] < 10)
{
while (counter[1] < 10)
{
TestChar = MakeChar(counter[1]);
if ((InChar[counter[0]] == TestChar) && (NotAfterD))
{
Temp = (Temp * 10) + counter[1];
}
if ((InChar[counter[0]] == TestChar) && (!(NotAfterD)))
{
Casting[0] = counter[1];
Casting[1] = counter[2];

Temp2 = (Casting[0]/(Casting[1] * 10));

Temp = Temp + Temp2;
counter[2] = counter[2] * 10;
}
if (InChar[counter[0]] == '.')
{
NotAfterD = false;
}
counter[1]++;
}
counter[0]++;
counter[1] = 0;
}
return Temp;
}

public static char MakeChar(int InNum)
{
char OutChar;
if (InNum == 0)
{
OutChar = '0';
}
if (InNum == 1)
{
OutChar = '1';
}
if (InNum == 2)
{
OutChar = '2';
}
if (InNum == 3)
{
OutChar = '3';
}
if (InNum == 4)
{
OutChar = '4';
}
if (InNum == 5)
{
OutChar = '5';
}
if (InNum == 6)
{
OutChar = '6';
}
if (InNum == 7)
{
OutChar = '7';
}
if (InNum == 8)
{
OutChar = '8';
}
if (InNum == 9)
{
OutChar = '9';
}
return OutChar;
}