Bash Arrays

Simon256 · 02-17-2009, 06:03 AM

Hi All.

Im currently attempting to write a script that takes the output of a command and put it into an array for me to 'play with' each item.

The problem I have is that it's currently treating the output as one item in the array as opposed to the nine items there actually is.

I run the command:

Code:

running=`su - zimbra -c "zmcontrol status"|grep Running| awk '{print $1}'|tr "\n" " "`
echo ${running[0]}

The command (starting from su -) returns a list of services. I attempt to format this into a space delmited list and pass this into a variable as an array.

However the entire list is becoming just one item in the array.

ie. the list is:
antispam antivirus ldap logger mailbox mta snmp spell stats

and echo ${running[0]} returns:
antispam antivirus ldap logger mailbox mta snmp spell stats

Any ideas what I'm doing wrong here?

Simon256 · 02-17-2009, 06:15 AM

Sorted, thanks.

Code:

#!/bin/bash
OIFS=${IFS}
IFS=$'\n'
running=($(su - zimbra -c "zmcontrol status"| grep Running | awk '{ print $1 }'))
arrayLen=${#running[@]}
echo "Number of elements : ${arrayLen}"
for (( i=0; i<${arrayLen}; i++ ));
do
  echo "${running[$i]}"
done

jan61 · 02-17-2009, 01:39 PM

Moin,

a little hint: You can do the grep work within the awk and save time and resources - and you don't need to redefine IFS:

Code:

running=($(su - zimbra -c "zmcontrol status"| awk ' /Running/ { printf "%s ",$1; }'))

Jan