[SOLVED] Arrange numbers in sequence from a variable

pedropt · 12-26-2017, 06:15 AM

This is probably a simple code , but i was looking in sort command and none of the switches work for this case .

for example :

Code:

#!/bin/bash
echo -n "Write a number not in order : "
read -r mynmb
varout=$(echo $mynmb | sort -n)

echo""
echo "You wrote : $mynmb  and was arranget in order by this : $varout"

basically i want to arrange :
example :

from : 283741 to 123478

This is probably simple , but i cant get into it directly from a variable .

keefaz · 12-26-2017, 07:11 AM

Probably the ugliest way

Code:

varout=$(echo -n $mynmb | fold -w1 | sort -n | tr -d "\n")

michaelk · 12-26-2017, 07:18 AM

Sort works on a data set or list not a single string.
Along the same line of thought... grep -o . separates the number before it gets piped to sort and recombined by tr.

Code:

$varout=$(echo $mynmb | grep -o . | sort | tr -d "\n")

Or perl

Code:

$varout=$(echo $mynmb | perl -F -lane 'print sort @F')

pedropt · 12-26-2017, 08:01 AM

Thanks guys , it works perfectly .

Let me just leave the correct code here finished for others to use :

Code:

#!/bin/bash
echo -n "Write a number not in order : "
read -r mynmb
varout=$(echo $mynmb | grep -o . | sort | tr -d "\n")

echo""
echo "You wrote : $mynmb  and was arranged in order by this : $varout"

keefaz · 12-26-2017, 08:28 AM

If the user doesn't know, I wonder what he/she will understand with:
"Write a number not in order"

I know I would be stuck at this point