Hello

I have a list of a whole bunch of cpp files, and their directories
for ex.

home/program/test.cpp
home/program/test1.h
home/personal/math.h
home/personal/iterate.cpp

Now I want to use ${varname%/*} to remove the names of the files and the last /, but i dont know how to use it. What should I put in carname?

x=$1
while [ "$2" ]
do
find $x -name "*.$2"
shift
done

the results should be like this
C/program/
C/personal/

as being the directories that contain cpp files

Thanks



I read file names off the command line, using $1, $2, I have the path saved in a variable called x
x=$1
in my loop i use find, and it prints the first list of directories

THanks for the hlep

Two programs that may be of use are "basename" and "cut" . See their "man pages" for details. Example:

man basename

Bash also has some string processing abilities built in. Here is the Advanced Bash-Scripting Guide:

http://www.linuxdoc.org/LDP/abs/html/index.html

Thanks, I took a look at the page and found something called dirname, which is the exact opposite of basename, and it worrks if I execute it on one line, but I would like to use it with find

find $x -name "*.$2"

where $x is my directory, and $2 are all the file extensions, it loops through any amount of command likes, so $2 is always changing

thanks again

actually dirname will not work with how i run my script
since i put
program /home/thegrepper/ cpp txt

but with dirname you need /home/thegrepper/cpp
so when i use dirname for program /home/thegrepper/ cpp txt
my dirname ends up being /home/

does anyone know how to use {var%/*} ?????????????

Darn, I guess no one can figure out what you mean by this: ${varname%/*} Where did you get that from anyways?