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Old 08-01-2011, 05:09 PM   #1
Fliggerty
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Finding the right file, with only a line and column number


I tried to come up with a thread title that was specific without being too long or cryptic. Don't think I succeeded.

In my PHP error log I keep getting this error over and over again:

Code:
EntityRef: expecting ';' at line 565, column 81
It's very odd to me that it doesn't contain any sort of stack trace or file info. I know which of my virtual hosts and therefore which directory it's coming from, and it's happened now on half a dozen different servers that this site has lived on.

So obviously I'm trying to track it down and add the missing ';' to the right file. This directory has dozens of sub-directories and hundreds of files though.

This is the best I've managed to come up with so far:

Code:
find . -type f -iname "*.php" -print -exec awk 'NR==565' {} \;
(I've run it both with and without the -iname filter.)

So I get a very large list of files, and some of them display the contents of line 565 after them. I've checked through a number of them there, but haven't found the culprit.

These are my questions:
  1. Is it possible to limit my "find" command to only files that have at least 565 lines?
  2. Is it possible to have it only print matches from line 565 that has at least 81 columns?
  3. How would I modify that to print perhaps 5 lines on either side (in case the error reporting is pulling a slightly different line.)
  4. Does anyone have any other suggestions on how I might track this thing down?

Thanks!
 
Old 08-01-2011, 05:42 PM   #2
crts
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Hi,

try this for a start:
Code:
find /path/to/dir -type f -name 'filename' -exec awk '{if (NR==565){if (length >= 81){print FILENAME": " $0}}}' {} \;
Notice, that 'find' does no longer print the filename. This is done by awk now only if the appropriate conditions are met.

Last edited by crts; 08-02-2011 at 10:15 AM.
 
Old 08-01-2011, 05:58 PM   #3
crts
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I have been thinking about the context issue. The fastest solution would be to implement this with the 'awk' statement. This is a bit complicated though and I do not have the time right now. As a quick 'n' dirty solution you could pipe the result to sed:
Code:
find . -type f -name 'filename' -exec awk '{if (NR==565){if (length >= 81){print FILENAME}}}' {} \; | xargs sed -n '560,570 p'
This will only print the filename if the conditions are met and sed is responsible for the printing. Notice, that xargs is necessary here.

Last edited by crts; 08-02-2011 at 10:16 AM.
 
Old 08-01-2011, 06:27 PM   #4
chrism01
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Presumably 'EntityRef' is a var? You should check for files containing that, at least 565 lines long
 
  


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