Dear All,
My manager asked me to find out all the jpg files in a directory and copy to another destination directory.I tried to write a shell script.But the problem is this source directory contains thousands of subdirectories.The jpg files resides in all of these directories.We have to search inside all these sub directories.I am reallyconfused.Can Any one help me.I am only a beginner to Shell scripting.Thanking YoU

Look at the manpage for the "find" command.
You can look for files with the pattern "*.jpg". You can use -iname to find files in a directory and it's subdirectories. The -iname argument is case insensitive.

Also look at the -exec argument.

example:
find /path/to/directory/ -iname "*.jpg" -execdir cp '{}' /path/to/dest/dir/ \;

Yes.That works Fine Thankyou.But one question too.Whether we can rename the files with directory name also.Because the file with similar names will be overwrited.Not at a big problem.Can u please try with this

Thats why I had put "cp -i" in my exec command - that will ask you just in case it finds multiple files with same name.

Hi

I have been trying to find files(Some hundres) from multiple directories.I have let us say 200 files in Heros.txt I need find and copy all those files from multiple subdirectroies under /data.Developed below script and executed it takes few secs and the completes with no action.I checked the destination folder but none was copied.Please share you idea to complete this task.


filename=/home/sankars/Heros.txt
count=0
while read LINE;
do
find /data -name LINE -exec cp '{}' /home/sankars/zip_thumbs \;
let count++
done < $filename


Thanks
Saravanan

You need a dollar sign in front of the LINE in find. The way it's written you're just searching for a file called LINE 200 times. The dollar sign in front tells it to substitute the contents of the variable LINE, rather than using the literal string "LINE". You should also add a trailing slash to the destination directory, so that it will error out if the directory doesn't exist. The way it's written it will copy each file, one by one, to a new file called "zip_thumbs", if the directory "zip_thumbs" doesn't already exist.

1 members found this post helpful.

These the shell script you can use to find and backup the jpg file from source to destination folder


#Script -Purpose:Backup script
# Exits with zero if no error.
#Before running the script create a folder /destination/jpg
#Function to copy the jpeg file form source to destination scripts



# Step -1 Function to archieve file using date and time

date=`/bin/date "+%Y.%m.%d.%H.%M.%S"`


# Step -2 Function to create folder on /root/logs with Timestamp

mkdir -p /destination/$date


# Step -3 Function to find & copy jpeg from /source to /destination


find /source/ -iname "*.jpg" -execdir cp '{}' /destination/$date \;


#Step -4 Function to compress the jpe copied file to /destination/jpg folder


tar -cvzf /destination/$date /destination/jpg/$date.tar.gz


#Step -5 Function to remove the copied jpg file

rm -rf /destination/*


#Step -4 Function to Print the logs Backup status

echo "$(date) jpg Backuped successfully ">>/destination/jpg/jpgbackup-status-$date.log

#Step -5 Function to trigger mail to user regarding backup status

mailid= $@gmail.com

#Step -5 Function to trigger mail after log backup status

mail -s '$(date) jpg copied Successfully $(hostname) - Successful' $mailid

Hi

Thanks for the advice..it works now..

Saravanan

Here are a couple of good links about using find:
http://mywiki.wooledge.org/UsingFind
http://www.grymoire.com/Unix/Find.html


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