[SOLVED] Listing file names side by side with directory names

anon84 · 04-03-2012, 04:24 AM

Hi Guys,

I am a novice in Unix and hoping that you will be able to help me out with the following
I have the follwing folder structure :

/work/test/User1/abcd1.txt
/work/test/User1/abcd12.txt
/work/test/User2/abcd21.txt
/work/test/User2/abcd22.txt
/work/test/User3/abcd31.txt
/work/test/User3/abcd32.txt
/work/test/User4/abcd41.txt
/work/test/User4/abcd42.txt
/work/test/User5/abcd51.txt
/work/test/User5/abcd52.txt

I am looking for a single command(not a script) which will produce an output like this:

User1 abcd1.txt
User1 abcd12.txt
User2 abcd21.txt
User2 abcd22.txt
User3 abcd31.txt
User3 abcd32.txt
User4 abcd41.txt
User4 abcd42.txt
User5 abcd51.txt
User4 abcd52.txt

Basically I want to list the directory names side by side with the filenames contained in each. Thanks in advance.

pan64 · 04-03-2012, 05:38 AM

Code:

ls  -1d /work/test/*/* | awk -F/ ' { print $4 " " $5 } '

anon84 · 04-03-2012, 06:22 AM

Thanks a lot..

..

grail · 04-03-2012, 10:13 AM

Please mark as SOLVED once you have your solution.