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Old 10-02-2010, 12:06 PM   #1
coffeeaddict19
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issue with checking for no arguments

This is my problem:

#!/bin/bash
NUMOFARGS=$#
if [ $NUMOFARGS="0" ]
then
echo "no arguments"
fi

When I run the above script it prints "no arguments" regardless of whether or not I supply arguments. I know this is probably an idiotic question, but how do I fix this?
 
Old 10-02-2010, 12:11 PM   #2
druuna
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Hi,

Mind the spacing: if [[ "$NUMOFARGS" = "0" ]]

Hope this helps.
 
Old 10-02-2010, 12:13 PM   #3
GrapefruiTgirl
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Also another idea:

Since $NUMOFARGS should contain an integer, why not compare it as an integer?
Code:
if [ $NUMOFARGS -eq 0 ]
 
Old 10-02-2010, 12:14 PM   #4
Dark_Helmet
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Quote:
Originally Posted by coffeeaddict19
Code:
if [ $NUMOFARGS="0" ]
You're mixing up numbers and strings. Bash treats them differently. Read up on the test command (man test)

What you want is something like this:
Code:
if [ $NUMOFARGS -eq 0 ]
Oh well, I'm late to the party, but I'm not letting my typing go to waste...
 
Old 10-02-2010, 12:20 PM   #5
coffeeaddict19
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Thanks for the help all, it works. I really appreciate the speedy response.
 
Old 10-03-2010, 01:15 AM   #6
grail
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Or you could use the more correct brackets:
Code:
if (( NUMOFARGS == 0 ))
And yes it is correct that the variable does not have a leading $
 
  


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