bash scripting question

methodtwo · 02-15-2009, 07:43 PM

'm learning bash but i don't understand how to call functions that are defined later.For example:

Code:

cmdz
function cmdz{
local cmd args
while read -e -p "> " cmd args; do
        case $cmd in
                sa ) select_all args ;;
                rd ) read_date args ;;
                ra ) read_attendee args ;;
                sd ) sorted_data args ;;
                q  ) exit
        esac
done
}

When i run this simple bit of code i just get an error saying that the "command" cmdz not found.So what is wrong here?
Any help would be great.Thankx in advance

weibullguy · 02-15-2009, 10:11 PM

I recommend you take a look at the Advanced Bash-Scripting Guide where you will read, "The function definition must precede the first call to it. There is no method of "declaring" the function, as, for example, in C."

raskin · 02-16-2009, 12:13 AM

Note that if you define a function A that calls function B, it is possible to define A before B if B is defined before the first call to A.