Bash Script to tell if a word is not! in a txt file??

Drigo · 01-30-2013, 02:57 PM

So, I have around 550 *.txt files that go under a process.
The output of that process has to finish with "all done"

So I want to create a bash script that checks each file, if the string "all done" is not found, I want to flag that file and output it.
Thanks in advance,

frieza · 01-30-2013, 03:29 PM

try

Code:

valuetocompare=`cat file.txt | grep "all done" | wc -l`

then use an if then else statement to act on the file if the value is a zero

thesnow · 01-30-2013, 03:57 PM

Could also use

Code:

grep -c "all done" file.txt

allend · 01-30-2013, 06:10 PM

Code:

#!/bin/bash
shopt -s globstar

for file in **/*.txt; do
  if [[ ! $(grep -q "all done" "$file") ]]; then
    echo "$file";
  fi
done

David the H. · 01-31-2013, 04:01 PM

No need for the test brackets:

Code:

#!/bin/bash
shopt -s globstar

for file in **/*.txt; do
  if ! grep -q "all done" "$file" ; then
    echo "$file"
  fi
done

In fact, there's no need for if, either.

Code:

for file in **/*.txt; do
  grep -q "all done" "$file" || echo "$file"
done

For more complex file matching, use a while+read loop and find:

How can I recursively search all files for a string?
http://mywiki.wooledge.org/BashFAQ/008

PS: globstar will choke up your shell if there happen to be any recursively-pointing symlinks in the subdirectories.