A script called by another script would always give exit status other than Zero(0)

vandana · 03-20-2010, 07:39 AM

Hi all

i m trying to execute 1st script into other script. I want the 1st script to put the exit staus into a log file .Also i want to ensure that 1st script will always give exit status other than Zero.Also i want to add text in log file.Like
if(success)then
echo "success:" exit status
if (failure) then
echo "failure:" exit status

Please help as i new to shell scripting.
Thanks
Vandana

David the H. · 03-20-2010, 08:17 AM

Your requirements are a bit unclear to me. Could you please explain what you want in more detail? What's the purpose of these two scripts and the relationship between them? How do you intend to call the second script from the first? How about some example code or pseudocode?

In general though, the exit status of a script is that of the last command it executes. Use the "exit" command to control what code is issued when the script exits (for example, add "exit 1" to the end of the script to make it output a status of 1). Finally, "$?" is used to get/output the exit status of the previous command.

"echo xyz >> filename" can be used to append lines to a file.

vandana · 03-22-2010, 04:26 AM

Quote:

Originally Posted by David the H.

Your requirements are a bit unclear to me. Could you please explain what you want in more detail? What's the purpose of these two scripts and the relationship between them? How do you intend to call the second script from the first? How about some example code or pseudocode?

In general though, the exit status of a script is that of the last command it executes. Use the "exit" command to control what code is issued when the script exits (for example, add "exit 1" to the end of the script to make it output a status of 1). Finally, "$?" is used to get/output the exit status of the previous command.

"echo xyz >> filename" can be used to append lines to a file.

Thanks David
now its working the way i wanted it.