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sncak

02-11-2021 02:07 AM

how to use sed command

I wanted to replace regex

Code:

-o '-p -- \\u'

with

Code:

--autologin wizard

using sed , i tried using

Code:

sed "s:-o /'-p -- \\u'/:--autologin wizard:" FILE

command but not working. can anyone suggest the best solution to this?

shruggy

02-11-2021 02:34 AM

Quoting is the problem, particularly handling of \\ inside double quotes. Try

Code:

echo "s:-o /'-p -- \\u'/:--autologin wizard:"

and you'll see what I mean. Adding another backslash or two would help:

Code:

echo "s:-o /'-p -- \\\u'/:--autologin wizard:"

Besides, there are no forward slashes (/) in the string you're trying to replace, but they are present in the sed expression?

sncak

02-11-2021 02:55 AM

I've tried the solution you have provided but it is not working.

Code:

sed "s:-o /'-p -- \\\u'/:--autologin wizard:"

I am still getting the unchanged output.

shruggy

02-11-2021 03:03 AM

Remove the forward slashes

Code:

sed "s:-o '-p -- \\\u':--autologin wizard:"

MadeInGermany

02-13-2021 08:30 AM

If you remember the rules

In the shell within a 'string in ticks'

a literal \ is a \
a literal ' is escaped '\''

And

a 'string in ticks' becomes a one-token string in ticks

And in sed

a literal \ is escaped \\

then it is straight forward

Code:

sed 's#-o '\''-p -- \\\\u'\''#--autologin wizard#'

sed gets

Code:

s#-o '-p -- \\\\u'#--autologin wizard#

and it substitutes

Code:

-o '-p -- \\u'

with

Code:

--autologin wizard

JJJCR

02-13-2021 09:10 AM

try this:

Quote:

sed -i -e 's/\\\\u/:--autologin wizard:/g' FILE

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